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PROGRAM TO FIND ANSWER OF THE FOLLOWING SERIES. SUM=X-X3/3!+X5/5!-X7/7!+...

 
#include<stdio.h>
#include<conio.h>
void main()
{
    long int x,i,j,k,n,sq,cnt;
    double fact,sum=0;
    clrscr();
    printf(\"\\n ENTER THE VALUE OF N: \");
    scanf(\"%ld\",&n);
    printf(\"\\n ENTER THE VALUE OF X: \");
    scanf(\"%ld\",&x);
    for(i=1,cnt=1;i<=n;i=i+2,cnt++)
    {
        for(j=1,sq=1;j<=i;j++)
        sq=sq*x;
        printf(\"\\n SQ = %ld\",sq);
        for(k=1,fact=1;k<=i;k++)
        fact=fact*k;
        printf(\"\\n fact = %7.2lf\",fact);

        if(cnt%2==1)
        sum=sum+(sq/fact);
        else
        sum=sum-(sq/fact);
        printf(\"\\n THE SUM OF THIS SERIES IS %7.2lf\\n\",sum);
    }
    getch();

}





****************************** OUTPUT *********************************



 ENTER THE VALUE OF N: 5

 ENTER THE VALUE OF X: 2

 SQ = 2
 fact =    1.00
 THE SUM OF THIS SERIES IS    2.00

 SQ = 8
 fact =    6.00
 THE SUM OF THIS SERIES IS    0.67

 SQ = 32
 fact =  120.00
 THE SUM OF THIS SERIES IS    0.93

**************************************************************************

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